12j^2+40j=7

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Solution for 12j^2+40j=7 equation:


Simplifying
12j2 + 40j = 7

Reorder the terms:
40j + 12j2 = 7

Solving
40j + 12j2 = 7

Solving for variable 'j'.

Reorder the terms:
-7 + 40j + 12j2 = 7 + -7

Combine like terms: 7 + -7 = 0
-7 + 40j + 12j2 = 0

Factor a trinomial.
(-7 + -2j)(1 + -6j) = 0

Subproblem 1

Set the factor '(-7 + -2j)' equal to zero and attempt to solve: Simplifying -7 + -2j = 0 Solving -7 + -2j = 0 Move all terms containing j to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2j = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2j = 0 + 7 -2j = 0 + 7 Combine like terms: 0 + 7 = 7 -2j = 7 Divide each side by '-2'. j = -3.5 Simplifying j = -3.5

Subproblem 2

Set the factor '(1 + -6j)' equal to zero and attempt to solve: Simplifying 1 + -6j = 0 Solving 1 + -6j = 0 Move all terms containing j to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -6j = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -6j = 0 + -1 -6j = 0 + -1 Combine like terms: 0 + -1 = -1 -6j = -1 Divide each side by '-6'. j = 0.1666666667 Simplifying j = 0.1666666667

Solution

j = {-3.5, 0.1666666667}

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